2hi g h2 g i2 g

1)For the reaction in the previous problem, that is, 2HI (g) ↔ H2 (g) + I2 (g) Keq = 0. Question: 6) a. Chemistry questions and answers.70 atm 13.15) K p = K ( R T) Δ n. Assuming all gases are at the same Question: The following reaction was performed in a sealed vessel at 721 ∘C∘C : H2(g)+I2(g)⇌2HI(g)H2(g)+I2(g)⇌2HI(g) Initially, only H2H2 and I2I2 were present at concentrations of [H2]=3. Determine the initial and equilibrium concentrations of HI if the initial concentrations of H2 and I2 are both 0.

 Therefore, in the reaction H₂(g) + I₂(g) → 2HI(g), both hydrogen and iodine change their oxidation states: Hydrogen from 0 to +1 and Iodine from 0 to -1

.6 g HI.984 mole of I2, and 0. 2HI (g) H2 (g) + I2 (g) Calculate the equilibrium concentrations of reactant and products when 0. Qc=[HI][H2][I2] There are 2 steps to solve this one. The potential energy of the reactants is indicated on the diagram.95×10-2 at 731 K.60 mol/L, [H2] = . The equilibrium constant, Kc, for the following reaction is 1.250 M 0.450 mol/L∙s.5x10^-3 atm and pHI=2.2. Who are the experts? Experts are tested by Chegg as specialists in their subject area.0156 at 400ºC. This is because the reaction is exothermic and releases heat.0% reacted at 731 K.2 kcal/mol (−9.353 moles of HI are introduced into a 1.39 M HI and no product. Consider the following exothermic reaction: 2HI (g) ⇆ H2 (g) + I2 (g) A) What will happen to the reaction mixture at equilibrium if an inert gas is added? [1] The equilibrium will shift to the left.072 M at 430 degree C.1 x 10-2 M, how many minutes will it take for the concentration to.50-L container initially holds 0.215 M H 2, and 0. Equilibrium concentration stays. These results can be used to calculate the standard Gibbs free … verified answered • expert verified H 2 (g)+I 2 (g)→2 H I (g) ΔH∘r x n=−9.00 L reaction vessel, chemical analysis determined these concentrations at equilibrium: [H2]=0.0 H―I 298. where K K is the equilibrium constant expressed in units of concentration and Δn Δ n is the difference … \[\ce{H2(g) + I2(g) \rightleftharpoons 2HI(g)} + \text{heat} \label{15.300 mol of H2 and 0. A flask originally contains 0.15) (15.87×10 −4 MM , and [I2]=[I2]= 4.2 at 430 degree C.200 M, and [HI] = 3.75 M I2, what is the equilibrium concentration of HI? The activation energy for the decomposition of Hi(g) to H2(g) and I2(g) is 186 kJ/mol. At a certain temperature, the equilibrium constant, Kc for this reaction is 53.550 mol HI was injected into a 2. With time, the concentrations of H2 and I2 decline, and the concentration of HI increases.033M, and 0. Express your answer using two significant The decomposition of HI (g) is represented by the equation 2HI (g) = H2 (g) + I2 (g) The following experiment was devised to determine the equilibrium constant of the reaction. H2(g)+I2(g)=2HI, Finding out final concentration of H2, I2 an… Balanced Chemical Equation 2 HI → H 2 + I 2 ⬇ Scroll down to see reaction info and a step-by-step answer, or balance another equation.] = 0.3 at 430 degree C. H2 (g) and I2 (g) can react to produce HI (g), as represented above. 1. Chemistry. Consider the reaction: 2 HI (g) ⇌ H₂ (g) + I₂ (g) Kc = 7.) b) Calculate the equilibrium constant, K. (a) Assuming ideal gas behavior, calculate the mass of H 2 present in the reaction mixture at equilibrium. Unlock. Drag the appropriate items to their respective bins.82 × 10-1.6 × 10−3 2 H I ( g ) → H 2 ( g ) + I 2 ( g ) ; At 25 C If 1. What is the equilibrium constant, KcKcK_c, for the The decomposition of HI is described by the following equations: 2HI(g) -----> H2(g) + I2(g) R = k [HI]2 At 400 oC, the rate constant k has the value 8. Calculate the equilibrium concentrations of the three gases. Since there is an equal number of each element in the reactants and products of H2 + I2 = 2HI, the equation is balanced.0 M HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25 ∘C , what is the equilibrium concentration of H2 (g)? a 0 H2 (g)+I2 (g)→2HI (g) ΔH∘rxn=−9.038 M H2, and 0.20M. Step 2.50 at 400∘C (b) H2( g)+I2( g) ⇌ 2HI(g) Kc = 50.6 × 10−3 at 25∘C. Find Ea. H2(g) + I2(g) ⇌ 2HI (g) = -9,6 kJ.100 atm. Consider the second-order reaction: 2HI (g)→H2 (g)+I2 (g) Use the simulation to find the initial concentration [HI]0 and the rate constant k for the reaction. [3] There is no effect on the equilibrium. ΔG°, for the reaction shown below at 453°C? 2HI(g) ↔ H2(g) + I2(g) Kp = 0.414 M, and [HI] = 3.65 M HBr and no product.27 mol/L I have the answer but need to see the work.0 L reaction container initially contains 22.55M. 2HI (g) H2 (g) + I2 (g) K = [H2] [I2] = 2. If an additional 1.90×1010 s ( [HI]t) for a reaction starting under the condition in the simulation? Chemistry questions and answers.65 M HBr and no product.75-L flask at a certain temperature initially contains 0. Phát biểu nào sau đây về sự trao đổi năng lượng của phản ứng trên là đúng? A. 2HI(g) > H2(g) + I2(g) Calculate Kc at this temperature for: H2(g) + I2(g) 2HI(g) Kc= 2.0175 mol/L.00623 mol of H2, 0. Expert Answer. at a particular temperature, K= 1. An additional 0.2. What will be the concentration of HI after t = 9.0 (c) CO2 (𝑔)+H2 (𝑔) CO (𝑔)+H2O (𝑔) T=980°C 𝐾𝑝=1. The equilibrium concentration of I2I2 is 0.2.708 atm, and PH2 = PI2 = 0. (Express your answer using two H2 (g) +I2 (g) <-----> 2HI (g) At equilibrium in a particular experiment, the concentrations of H2,I2 , and HI were 0. [HI] = M [H2] = M [I2] = M. So, this is indeed a redox reaction because oxidation (the loss of electrons as seen in The equilibrium constant, Kc, for the following reaction is 1.0 (at 400ºC) If the reaction vessel initially contains 0. 2HI(g)⇌H2(g)+I2(g) Kc=[H2]/[I2][HI]^2. The value of Keq for this reaction is _____.393 M. Part A. The rate constant at 555 K is 3.80×10-2 at 698 K.)The equilibrium constant, Kc, for the following reaction is 1. What is the equilibrium concentration of H2? Question: Hydrogen iodide decomposes according to the equation 2HI (g) H2 (g) + I2 (g), for which Kc = 0.51x10^-9 L/mol*s) ( (1/ The value of Keq for the equilibrium H2 (g) + I2 (g) ⇌ 2HI (g) is 794 at 25 °C.25 Consider the reaction: H2 (g) +I2 (g) 2 HI (g) A reaction mixture in a 3.45 M HI and no product. Q.0 g of l2 (g). About us.59×10 −3 MM , [H2]=[H2]= 4.

00 mole of H2, 1

. Suggest Corrections.0 M HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25∘C, what is the equilibrium concentration of H2 (g)? Question: Consider the second-order reaction: 2HI(g) →H2(g) + I2(g) Use the simulation to find the initial concentration (HI), and the rate constant k for the reaction. At this temperature, what is the value of Keq for the equilibrium below? HI (g) ⇋1/2 H2 (g) + 1/2 I2 (g) 2.761 g H2 and 96.9 and 4 over a wide temperature range (100-1000 K).0300 M . A reaction vessel contains 0. 0.00 x 102 for the reaction H2 (g) + I2 (g) <-> 2HI (g) In an experiment, 1. H2 (g)+I2 (g)↽−−⇀ 2HI (g)𝐾= [HI]2 [H2] [I2]H2 (g)+I2 (g)↽−−⇀ 2HI (g)K= [HI]2 [H2] [I2] For the reaction 2HI (𝑔)↽−−⇀ H2 (𝑔)+I2 (𝑔)2HI (g)↽−−⇀ H2 (g)+I2 (g) select the equilibrium constant Hydrogen iodide can decompose into hydrogen and iodine gases.3=]2H[M57. What is the value of Keq for the equilibrium below? 1/2H₂ (g) + 1/2 I₂ (g) ⇌ HI (g), The value of Keq for the equilibrium H₂ (g) + I₂ (g) ⇌ 2 HI (g) is 794 at 25°C. only products are Question: Consider the second-order reaction: 2HI(g)→H2(g)+I2(g) Use the simulation to find the initial concentration [HI]0 and the rate constant k for the reaction. 2SO3(g) > 2SO2(g) + O2(g) Calculate Kc at this temperature for the following reaction: SO3(g H2, I2, and HI are introduced into a flask. 2HI(g)?H2(g)+I2(g) Determine the reaction quotient expression for the reversible reaction below.40-L reaction chamber. Mar 4, 2018 #K_c = 2. The law of mass action best fits which of the following descriptions? Find the equilibrium expression for the reversible reaction below. 0. What is the free energy change, ΔG°, for the Question. View Available Hint (s)for Part A Reset Help System A Increase HI decomposes to H2 and I2 by the following equation: 2HI(g) → H2(g) + I2(g);Kc = 1.484 M , [I2]=0. (a) N2 (𝑔)+O2 (𝑔) 2NO (𝑔) T=2000°C 𝐾𝑝=4. Unlock. H2 (g)+I2 (g)⇌2HI (g) has Δ H =−2. For the following systems at equilibrium A:B:2NOCl (g)H2 (g)+I2 (g)⇌⇌2NO (g)+Cl2 (g)2HI (g)A:2NOCl (g)⇌2NO (g)+Cl2 (g)B:H2 (g)+I2 (g)⇌2HI (g) classify these changes by their effect. What is the equilibrium concentration of H2? 2)For the reaction: 2HBr (g) ↔ H2 (g) + Br2 (g) Initially a container contains 0. Ở nhiệt độ không đổi, khi tăng áp suất thì cân bằng không bị chuyển dịch. Part A.0552 mol of HI in a volume of 735 cm3 . H2 (g)+I2 (g) = 2HI (g) At this temperature, 0.2. Flashcards; Test; Learn Study with Quizlet and memorize flashcards containing terms like The value of Keq for the equilibrium H₂ (g) + I₂ (g) ⇌ 2HI (g) is 794 at 25 °C.10M and [I2]=2. At this temperature, what is the value of Keq for the equilibrium You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Question: At 500 °C, hydrogen iodide decomposes according to 2HI(g)↽−−⇀H2(g)+I2(g) For HI(g) heated to 500 °C in a 1.708 atm, PH2 = PI2), we can substitute them into the equilibrium expression for the reaction, which is Kp = (PH2 * PI2) / (PHI)^2.2. We reviewed their content and use your Final answer.42 mol of CO and 0. products predominate b.35 M0.00 mole of I2, and 1.0×10−3M and the initial concentrations of H2, and the initial concentrations of H2, and I2 are both 1. 1 Answer Stefan V. The equilibrium constant, Kc, for the following reaction is 1.noinU teivoS eht fo ytic tsegral dna latipac eht ,wocsoM no kcatta s'reltiH detartsurf troffe evisnefed teivoS ehT.Q. Calculate K for 2HI (g)⇌H2 ( g)+I2 ( g) at this temperature. Calculate the concentrations of the gases at equilibrium.714 mole of H2, 0.0 g of HI (g) is injected into a 4.4 H2(g) 0 I―I 151 I2(g) 61.87×10 −4 MM . (b) What is the percent yield of the reaction under these conditions? (not answered) Consider the following exothermic reaction below.550 mol HI is injected into a 2. Science. What will be the concentration of HI after t = 9. Who are the experts? Experts have been vetted by Chegg as specialists in this subject.0 minutes? 1 pts. Who are the experts? Experts have been vetted by Chegg as specialists in this subject. Answer: Increasing the temperature will cause the equilibrium to shift towards the reactants (left). If the initial concentration of HI in a container is 5.80×10-2 at 698 2HI(g) --> H2(g) + I2(g) Rate = -d[HI]/dt = k = 1. The equilibrium constant for a system will be symbolized by the letter: K.22. 2HI (g) leftright arrow H2 (g) + I2 (g) What will happen to the reaction mixture at equilibrium if some H2 (g) is removed? A) The equilibrium will shift to the left.3. How does the magnitude of Kp for the reaction 2HI(g)⇋H2(g)+I2(g) change if the equilibrium is written 6HI(g)⇋3H2(g)+3I2(g)? It is cubed. Consider the reaction H2(g) + I2(g) <--> 2HI(g).1×10−4 (b) H2 (𝑔)+I2 (𝑔) 2HI (𝑔) T=400°C 𝐾𝑝=50. Which statement is correct about this reaction mixture? View Available Hint(s) The equilibrium constant, Kc, for the reaction H2 (g) + I2 (g) ⇄ 2HI (g) at 425°C is 54.0890 M HI, 0.5kJ/molrxn. At equilibrium, _____. Nhận xét nào sau đây không đúng? A.8×10−2 at 700 K.10x10^-5 L/mol*s / 9. Consider the following chemical reaction: CO (g) + 2H2 (g) ⇋CH3OH (g) At equilibrium in a particular experiment, the concentrations of CO Question: Consider the second-order reaction: 2HI(g)→H2(g)+I2(g) Use the simulation to find the initial concentration [HI]0 and the rate constant k for the reaction.00 L vessel at 698 K. Show transcribed image text. Chemistry Chemistry questions and answers Determine the reaction quotient expression for the reversible reaction below.353 moles of HI are introduced into a 1. At 500 °C, hydrogen iodide decomposes according to 2 HI (g) — H2 (g) +1_ (8) For HI (g) heated to 500 °C in a 1. 0. 0. Part A Calculate the equilibrium constant (Kc) for the reaction at this temperature.43 atm b! 3.85 mol/L, [I2] = . If the initial concentration of HI in a container is 3. Thank you. Study with Quizlet and memorize flashcards containing terms like 42) Of the following equilibria, only _____ will shift to the left in response to a decrease in volume.0.52 x 10-7 L/mols. Chemistry questions and answers.60 mol/L, [H2] = 0.9 g I2. See answers.0890 M HI, 0.55M respectively. Show transcribed image text.220 M e.80×10-2 at 698 2HI(g) --> H2(g) + I2(g) Rate = -d[HI]/dt = k = 1. 2HI(g) H2(g) I2(g) K for the reaction is 0. The law of mass action best fits which of the following descriptions? Find the equilibrium expression for the reversible reaction below.020 H2 (g) + I2 (g) → 2HI (g) What is the free energy change, Δ G ° (kJ), for the equilibrium between Chemistry question on rate laws.15 K are summarized in Table 4. At the start of the reaction there are 0. The reaction described by H2 (g) + I2 (g) yields 2HI (g) has an experimentally determined rate law of rate of reaction= k [H2] [I2]some proposed mechanisms for this reaction are: Mechanism a. Kc = 56. 2HI(g)?H2(g)+I2(g) Here’s the best way to solve it.040; This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts.75 M H2 and 0.80×10-4 mol L-1 s-1 If the experiment has an initial HI concentration of 0. The equilibrium constant, Kp, for the reaction H2(g) + I2(g) ⇌ 2HI(g) at 25°C can be calculated using the standard Gibbs free energy change, ΔG°, of 2. So if you add heat, more N2 (g) and H2 (g) will be created and balance out the reaction. What is the activation energy of this reaction? Question: Given a reversible chemical reaction: H2(g) + I2(g) ⇌ 2HI(g) Kc = 64. 0.78 atm O 0. Calculate K for this reaction. Qc=[HI][H2][I2] There are 2 steps to solve this one.2^]IH[]2I[/]2H[=cK )g(2I+)g(2H⇌)g(IH2 .20 M of H₂ and 1. loading. Step 1.

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Use data from Appendix C to calculate the equilibrium constant, K, and Δ G ∘ at 298 K for each of the following reactions.00 mole of HI are introduced into a 1.0249 0. There are 2 steps to solve this one. Of 0. Shown below is an incomplete energy diagram for the reaction.0535 0.43×10-2 at 1110 K. C.00 L vessel at 698 K.314 J/molK) (ln 1.70 M0. 2HI(g) = H2(g) + I2(g) Calculate Kc at this temperature for the following reaction: HI(g) =1/2H2(g) + 1/2I2(g) This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. What will be the concentration of HI after t = 4.10x10^-5 L/mols / 9.016 Initially a container contains 0.4 x 10-2 M, how many minutes will it take for the concentration to be reduced to 8. Drag the appropriate items to their respective bins.13 M1.00 mol of HI (g) is introduced into the reaction vessel In which direction will the position of the equilibrium be shifted for each of the following changes? Explain your answers.0156 at 400ºC. [HI] = M [H2] = M [I2] = M.040; This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts.00414 mol of I2, and 0. Express your answer in moles per liters to three significant figures.040. When the system comes to equilibrium at 400°C, what will be the total pressure inside the reaction vessel? 2HI (g) % H2 (g) + 12 (g), Kc = 0.0 si IH fo noitartnecnoc eht deveihca si muirbiliuqe nehW )g(IH2 )g(2I + )g(2H . The standard free energy of formation of gaseous hydrogen iodide is1.15M and [I2]=2. The equilibrium constant for a system will be symbolized by the letter: K.00 L reaction vessel that contains 20. What is the equilibrium concentration of H2? 2)For the reaction: 2HBr (g) ↔ H2 (g) + Br2 (g) Initially a container contains 0. Question: Gaseous hydrogen iodide is placed in a closed container at 425∘C, where it partially decomposes to hydrogen and iodine: 2HI(g)⇌H2(g)+I2(g) At equilibrium it is found that [HI]= 3.638 0.2 kJ/mol). Russia said it had suppressed a drone attack on Moscow carried out by Ukraine which it has accused of "international terrorism.4x10^-2 atm, pI2=4. B. Find [H2] at 340 ∘C .4 kg of CO 2 at 825 K.6 x 10-3 L mol-1s-1 at 700 ºC.00 mol of HI(g) is introduced into the reaction vessel, what are 2HI(g)⇌H2(g)+I2(g) Select the correct answer below: Qc=[HI]2[H2][I2] Qc=[H2][I2][HI] Qc=[H2][I2][HI]2. 1.200 atm, and a partial pressure of HI of 0., As the reaction quotient Q increases, what is the effect on the Chemistry questions and answers. s. a) H2 ( g )+I2 ( g )⇌2HI ( g) Calculate Δ G ∘.5 L container at 758 K, the value of the equilibrium constant, Kc, is. At equilibrium, the flask contains 90. At equilibrium, pH2= 1. Step 1.87×10 −4 MM , and [I2]=[I2]= 4. Chemistry Chemistry questions and answers For the reaction 2HI (g)⇌H2 (g)+I2 (g), the equilibrium constant Kc=1. H2(g) + I2(g) → 2HI (g) ∆H = +11,3 kJ. Find Ea.67 (d) CaCO3 (𝑠) CaO (𝑠)+CO2 At 25°C, the equilibrium constant, Kp, for the reaction H2(g) + I2(g) ⇌ 2HI(g) is approximately 0.T.016 Initially a container contains 0. Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced. View the full answer. Similar questions.64 moles of HI (g), 0.9 g I2. Chemistry. 1, 2023.76×1010 s ([HI]t) for a reaction starting under the condition in the simulation? Express your answer in moles per liters to three significant figures.498 M I2.21 If at equilibrium the reaction vessel contains 1. Consider the equilibrium system involving the decomposition of hydrogen iodide.83×10−4 M .60 kJ/mol. Expert-verified.148 atm of HI(g) is sealed in a flask, what is the pressure of each gas when equilibrium is established What is the standard free energy change, ΔG°, for the reaction shown below at 453°C? 2HI(g) ↔ H2(g) + I2(g) Kp = 0.s-1 : 2HI (g) → H2 (g) + I2 (g) 1) Based on the units of the rate constant, is the reaction first order or second order? Explain. a) Carefully complete the energy diagram by drawing a curve that accurately shows the progress of Question: Consider the following reaction for the decomposition of HI at a certain temperature 2HI(g) --> H2(g) + I2(g) the average rate of disappearance of HI over the period from t = 0 to t = 5. Consider the following reaction: 2HI (g) H2 (g) + I2 (g) If 3. Suggest Corrections. For the reaction 2HI(g) H2(g) +I2(g), the degree of dissociation (a) of HI(g) is related to equilibrium constant kp by the relation? Open in App. H2 (g) + I2 (g) yields (k1 on top of the arrow) 2HI (g) (one step reaction)Mechanism b.15 M I2 at equilibrium. Chemistry. Question: What is the free energy change, ΔG°, for the equilibrium between hydrogen iodide, hydrogen, and iodine at 311°C? Kc = 0.B. The reaction is second order and has a rate constant equal to 1. For the reaction H2(g) + I2(g) ⇌ 2HI(g) K= 57.Moscow was one of the primary military and political It was the latest step in an ongoing crackdown on L.2. You'll get a detailed solution from a subject matter expert that helps you learn core concepts. At this temperature, what is the value of Keq for the equilibrium below? HI (g) ⇌ 1/2 H2 (g) + 1/2 I2 (g) The value of Keq for the equilibrium H2 (g) + I2 (g) 2HI (g) is 794 at 25 °C.50 M? [H2] = 0. The value of Keq for the equilibrium H2 (g) + I2 (g) 2 HI (g) is 794 at 25 °C. Reaction Information Word Equation Hydrogen Iodide = Dihydrogen + Diiodine Consider the gas-phase reaction H2 (g) + I2 (g) ⇄ 2 HI (g) Suppose that a sealed flask containing H2 and I2 has been heated to 425 °C and the initial concentrations of H2 and I2 were each 0. 25. This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts.53×1010 s ([HI]t) for a reaction starting under the condition in the simulation? Given from simulation: Rate Law: k[HI]^2 k= 6.00-L flask containing an equilibrium mixture of the three gases, there are 0. The reaction.0049. 2) Suppose a reaction is started with 0. ΔG°, for the reaction shown below at 453°C? 2HI(g) ↔ H2(g) + I2(g) Kp = 0. The temperature is expressed as the absolute temperature in Kelvin. Consider the equilibrium reaction and its equilibrium constant expression.30 kJ/mol at 25°C.00 × 10^−19 at 298 K what can be said about this reaction at this temperature? The equilibrium lies far to the left. Shown below is an incomplete energy diagram … For the reaction 2HI(g) H2(g) +I2(g), the degree of dissociation (a) of HI(g) is related to equilibrium constant kp by the relation? Open in App.95M[I2]=2. H2 (g) + I2 (g) yields (k1 on top of the arrow) 2HI (g) (one step reaction)Mechanism b.390 mol/L, what is the concentration of HI after 28.38 x 10-4 mol-1 L s-1 and at 500 oC, the rate constant k has the value 7. Chemistry questions and answers. Tổng nhiệt phá vỡ liên kết của chất phản ứng lớn hơn nhiệt tỏa ra khi tạo thành Question: Hydrogen iodide decomposes according to the equation 2HI(g) H2(g) + I2(g), for which Kc = 0.100 M, [I2] = 0.The amount of I2 produced over time is measured by opening each 2HI(g)⇌H2(g)+I2(g)2HI(g)⇌H2(g)+I2(g) At equilibrium it is found that [HI]=[HI]= 3.6 × 10−3 at 25∘C If 1.00-L reaction vessel at 400ºC. Shown below is an incomplete energy diagram for the reaction.122 at For the reaction 2HBr(g) ⇌ H2(g) + Br2(g) K = 2.643 moles of I2 are at equilibrium in a 17. B. In a certain experiment the decomposition of hydrogen iodide on finely divided gold is zeroth order with respect to HI.80×10-2 at 698 K.00 L container to react.60 mol/L, [H2] = .25 * 10^(3)# Explanation: You Step 4: Substitute Coefficients and Verify Result.314 J/molK) (ln 1.50 M. HI (g) is introduced into five identical 400-cm3 glass bulbs, and the five bulbs are maintained at 623 K. 0. (Please show me the step-by-step math needed to achieve this 2 H I (g) ⇌ H 2 (g) + I 2 (g), For the above reaction the degree of dissociation ( α ) of HI (g) is related to equilibrium constant K p by the expression : View Solution The concentrations of HI and I2 will increase as the system is approaching.09 M .K 007 ta 3.275 M The value of Keq for the equilibrium.498 M I 2. Show below how to derive the Keq . What is the value of KcKc at this temperature? Express the equilibrium constant to three significant digits. Given the partial pressures of HI, H2 and I2 at equilibrium (PHI = 0. Calculate the concentration of HI at equilibrium. What is the value of Keq for the equilibrium below? 1/2 H2 (g) + 1/2 I2 (g) HI (g) A) 1588 B) 0. Calculate the magnitude of Kc for the reaction.53 M0.100 mol I2 were placed in a 1.07x1010 s ( [HI]+) for a reaction starting under the condition in the simulation? Express your answer in moles per liters to three significant figures.9. The equilibrium concentration of I2 is 0.3 kg of CH 4 and 55. Chemistry questions and answers..708 atm, and PH2=P12=0.200 M, and [HI] = 3.550 mol HI was injected into a 2.9) The equilibrium constant expression for this reaction is.484 M , [I2]=0. Consider the following system at equilibrium at 698 K: 2HI (g) H2 (g) + I2 (g) When some HI (g) is added to the equilibrium system at constant temperature: The reaction must: fill in the blank 1 A.0 atm. Chemistry.7. Step 2. 2HI (g)?H2 (g)+I2 (g) This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. You'll get a detailed solution from a subject matter expert that helps you learn core concepts.06 M The equilibrium constant, K c, for the reaction H2 (g) + I2 (g) ⇄ 2HI (g) at 425°C.6x10^-1 atm.51 x 10^-9 L/mols at 500 K and 1. At this temperature, what is the value. A reaction vessel is charged with hydrogen iodide, which partially decomposes to molecular hydrogen and iodine:2HI (g) ↔ H2(g) + I2(g)When the system comes to equilibrium at 425 °C, PHI = 0. Count the number of atoms of each element on each side of the equation and verify that all elements and electrons (if there are charges/ions) are balanced.390 mol/L, what is the concentration of HI after 28. K = [HD]2 [H2][D2] (15. Step 4: Substitute Coefficients and Verify Result.2Group of answer choices0. The equilibrium constant, Kc, for the following reaction is 1. Expert-verified. Question: At 500 °C, hydrogen iodide decomposes according to 2HI(g)↽−−⇀H2(g)+I2(g) For HI(g) heated to 500 °C in a 1. The following reaction was performed in a sealed vessel at 723 ∘C : H2 (g)+I2 (g)⇌2HI (g) Initially, only H2 and I2 were present at concentrations of [H2]=3. B. If an additional 1.87×10 −4 MM . Flashcards; Test; Learn Study with Quizlet and memorize flashcards containing terms like The value of Keq for the equilibrium H₂ (g) + I₂ (g) ⇌ 2HI (g) is 794 at 25 °C. HI (g) is introduced into five identical 400-cm3 glass bulbs, and the five bulbs are maintained at 623 K.484 M , and [HI]=4.0013 verified answered • expert verified H 2 (g)+I 2 (g)→2 H I (g) ΔH∘r x n=−9. Question: Assuming all gases are at the same temperature and pressure, how many milliliters of hydrogen iodide are produced from 150 mL of H2? H2 (g)+I2 (g)→2HI (g) Express your answer with the appropriate units. In a 2. B.295. For the reaction H2(g)+I2(g)⇌2HI(g), Kc = 55. freedom in Russia, including a law passed in December against depictions of gay lifestyles — what the government called "gay Investigators examine an area next to a damaged building in the "Moscow City" business district after a reported drone attack in Moscow, Russia, early Tuesday, Aug. Suppose 0. please do step by step. What concentration of HI is present at equilibrium? 2HI (g) -> H2 (g) + I2 (g) There are 2 Hydrogen atoms and 2 Iodine atoms on the right so the have to be 2 of each on the left as well, so there are 2 HI molecules on the left. For the reaction in the previous problem, that is, 2HI (g) ↔ H2 (g) + I2 (g) Keq = 0. Chemistry questions and answers.059 g H2 and 4. Find Kp for the reaction 2HI (g) H2 (g)+ I2 (s) at this temperature.80×10-4 mol L-1 s-1 If the experiment has an initial HI concentration of 0. + 2 H2(g) ⇌ CH3OH (g)In an experiment, 0. H2 (g) + I2 (g) ⇋2HI (g) is 794 at 25 °C. Question: What is the free energy change, ΔG° (kJ), for the equilibrium between hydrogen iodide, hydrogen, and iodine at 453°C? Kc = 0.28×10 10 s ([HI]t) for a reaction starting under the condition in the simulation?. H2 (g) + I2 (g) → 2HI (g) A student makes the following statements: Hydrogen always has the same oxidation number, so it has an oxidation number of +1 in both the reactant H2 and product HI.. Question: The decomposition of hydrogen iodide, 2HI (g) ----> 2H2 (g) + I2 (g), has rate constants of 9.16 M and their equilibrium concentrations are both 0. 2HI (g) H2 (g) + I2 (g) Calculate the equilibrium concentrations of reactant and products when 0. 21.56×10−3 M , [H2]= 4.15 298. The rate constant at 555 K is 3. Calculate Kc for the reaction 2HI(g) = H2(g) + I2(g) given that the concentration of each species at equilibrium are as follows: [HI] = 0. Express your answer using two significant The decomposition of HI (g) is represented by the equation 2HI (g) = H2 (g) + I2 (g) The following experiment was devised to determine the equilibrium constant of the reaction. C.00 L reaction vessel at 400ºC.50 M? [H2] = 0.10) with K varying between 1. Study with Quizlet and memorize flashcards containing terms like If a given process proceeds spontaneously toward the products, the value of the reaction quotient Q is _ the equilibrium constant K, and ΔG for the reaction will be _.00 L vessel at 698 K.200 mol H2 and 0.6} \] Increasing the temperature of the reaction increases the internal energy of the system. Find step-by-step Chemistry solutions and your answer to the following textbook question: Hydrogen iodide decomposes according to the reaction $2 \mathrm { Hl } ( \mathrm { g } ) \rightleftharpoons \mathrm { H } 2 ( \mathrm { g } ) + 12 ( \mathrm { g } )$ A sealed 1. Who are the experts? Experts have been vetted by Chegg as specialists in this subject. a.) Convert the values of Kc to values of K p or the values of K p to values of Kc.00 L reaction vessel at 400ºC. Calculate the concentration of HI at equilibrium.50 M? 613. About Quizlet; How Quizlet works; Careers; Advertise with us; Get the app; For students. The equilibrium constant, Kc, for the following reaction is 1. To form HI The equilibrium constant, Kc, for the following reaction is 1.00-L container. Iodine is in Group VIIA, so it has an oxidation number of -1 in both the reactant I2 and product HI. 2HI (g) → H2 (g) + I2 (g) The rate constant for this reaction is 1. (Express your answer to four significant figures and include the appropriate units. The equilibrium constant Kc for the reaction H2 (g) + I2 (g) <=> 2 HI (g) is 54. Please show work.886 mole of HI in a 2.0 x 10-4 M? Question: Calculate ΔG° for each of the following reactions from the equilibrium constant at the temperature given. Shown below is an incomplete energy diagram for the reaction. The equilibrium constant, Kp, is related to the standard Gibbs free energy change, ΔG°, through the equation: Find Kc for the reaction. What is the equilibrium constant for the reaction H2(g)+I2(g)⇌2HI(g) at 700 K? Express your answer using two significant figures. … Kp = K(RT)Δn (15.8. [2] The equilibrium will shift to the right.6 x 10-3 L mol-1 s-1 at 700 °C. 2H18) <--> H2(g) + 12(g) + heat Shift (Left, Right, or no shift) Change Reason Hydrogen is added lodine is removed Some argon is added Volume of container is doubled Volume of container is doubled Temperature is decreased The reaction vessel is heated Edit View Insert Consider the second-order reaction: 2HI(g)→H2(g)+I2(g) Use the simulation to find the initial concentration [HI]0and the rate constant k for the reaction. H2 (g) + I2 (g) yields (k1 on top of the arrow) 2HI (g) (one step reaction)Mechanism b.

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Thus, increasing the temperature has the effect of increasing the amount of one of the products of this reaction. 0. 2HI (g) = H2 (g) + I2 (g) Calculate Kc at this temperature for the following reaction: HI (g) =1/2H2 (g) + 1/2I2 (g) 6) a CO2 g+H2 g⇌CO g+H2O g.038 but I need detailed steps how to get there.32 g I2. Thanks! HI decomposes to H2 and I2 by the following equation: 2HI (g) → H2 (g) + I2 (g);Kc = 1. A) 4 Fe (s) + 3 O2 (g) 2 Fe2O3 (s) B) H2 (g) + Cl2 (g) 2 HCl (g) C) 2HI (g) H2 (g) + I2 (g) D) 2 SO3 (g) 2 SO2 (g) + O2 (g) E) N2 (g) + 3 H2 (g) 2 NH3 (g), 43) Of the following equilibria, only _____ will shift to the left in H2(g)+I2(g)⇌2HI(g) Initially, only H2 and I2 were present at concentrations of [H2]=3. calculate the concentrations of all species when equilibrium is reached. See Answer Chemistry Chemistry questions and answers Hydrogen iodide decomposes according to the equation 2HI (g) H2 (g) + I2 (g), for which Kc = 0.2HI (g) -> H2 (g) + I2 (g) There are 2 Hydrogen atoms and 2 Iodine atoms on the right so the have to be 2 of each on the left as well, so there are 2 HI molecules on the left. Since there is an equal number of each element in the reactants and products of H2 + I2 = 2HI, the equation is balanced. Chemistry questions and answers.02×10-2 at 907. What will be the concentration of HI after t = 4. (a) N2( g)+ 3H2( g)⇌ 2NH3( g) Kc = 0.0960 atm. Chemistry questions and answers. Thus, increasing … H2 (g) + I2 (g) → 2HI (g) A student makes the following statements: Hydrogen always has the same oxidation number, so it has an oxidation number of +1 in … H2(g) and I2(g) can react to produce HI(g), as represented above.srewsna dna snoitseuq yrtsimehC .550 M b.035 C) 28 D) 397 E) 0.95M.80M. where K K is the equilibrium constant expressed in units of concentration and Δn Δ n is the difference between the numbers of moles of gaseous products and gaseous reactants ( np −nr n p − n r ).00 L vessel where the following equilibrium was established: H2 + I2 <-----> 2HI For this reaction, Kc = 49.85 mol/L, [I2] = .00 L reaction vessel, chemical analysis determined these concentrations at equilibrium: [H2]=0.2 at 448∘C (c) Na2SO4 ⋅ 10H2O (s) ⇌ Na2SO4( s)+ 10H2O (g) KP = 4. What is the value of Kc at this temperature? Chemistry questions and answers.6} \] Increasing the temperature of the reaction increases the internal energy of the system." Russian media reported that two unmanned The Battle of Moscow was a military campaign that consisted of two periods of strategically significant fighting on a 600 km (370 mi) sector of the Eastern Front during World War II, between September 1941 and January 1942.5 k J/m o l r x n H 2 (g) and I 2 (g) can react to produce HI (g) , as represented above. Question: The decomposition of hydrogen iodide, 2HI (g) ----> 2H2 (g) + I2 (g), has rate constants of 9.s at 500 K Express your answer in moles per liters to On one set of axes, sketch concentration vs time curves for H2 and HI. The system H2(g) + I2(g) ⇌ 2HI(g) is at equilibrium at a fixed temperature with a partial pressure of H2 of 0. Answer to Solved Calculate Kc for the reaction 2HI(g) = H2(g) + I2(g) Science; Chemistry; Chemistry questions and answers; Calculate Kc for the reaction 2HI(g) = H2(g) + I2(g) given that the concentration of each species at equilibrium are as follows: [HI] = 0. The equilibrium constant (Kc) for the reaction H2 (g) + I2 (g) <=> 2HI (g) is 54.10 x 10^-5 L/mols at 600 K.200 atm, a partial pressure of I2 of 0. Phản ứng giải phóng nhiệt lượng 11,3 kJ khi 2 mol HI được tạo thành.0 M HI is placed into a closed container and the reaction is allowed to reach equilibrium at 25∘C, what is the equilibrium concentration of H2 (g)? The equilibrium constant, Kc, for the reaction H2 (g) + I2 (g) ⇄ 2HI (g) at 425°C is 54. Chemistry.072 M, what was the initial concentration of HI? H2 (g) + I2 (g) ⇌ 2HI (g) Kc=54. Run in the reverse direction to restablish equilibrium. The rate constant for the decomposition of hydrogen iodide (HI) at 700oC equals 0. Solution.50 M? 613. 0. If the initial concentrations of H2 and I2 are both 0.42 mol of H2 were placed in a 1. 21. For the reaction 2HI (g) ⇌H2 (g)+I2 (g), Kc= 0.100 M, [I2] = 0. The equilibrium constant, Kc, for the following reaction is 1. ÐÏ à¡± á> þÿ h j Exercise 14.08 ×10 −25 at 25∘C (d) H2O(I) ⇌ H2O(g) KP = 0.428 moles of H2, and 0. Thus an equilibrium mixture of H2, D2, and HD contains significant concentrations of both product and reactants.0156 at 400ºC.42 times 10^{-7} L/mol .27 mol/L I have the answer but need to see the work.100 M, [I2] = 0. What is the standard free energy change, ΔG°, for the reaction shown below at 453°C? 2HI(g) ↔ H2(g) + I2(g) Kp = 0. 2HI(g) H2(g) + I2(g) Calculate the equilibrium concentrations of reactant and products when 0.100 M, [I2] = 0. 1.016 Initially a container contains 0.75-L flask at a certain temperature initially contains 0.0156 at 400°C 單選: 2. What is the value of KcKc at this temperature? Express the equilibrium constant to three significant digits. What is the rate of appearance of I2 over the same period? a.26 atm pressure of HI is admitted to the container, and it is allowed to come to equilibrium again. What is the equilibrium constant, Kc, for the reaction at this temperature? H2(g)+I2(g)⇌2HI(g) Initially, only H2 and I2 were present at concentrations of [H2]=3. Chemistry questions and answers. An 85.0960 atm.83×10−4 M , and [I2]= 4. H2(g) +D2(g) ⇌ 2HD(g) (15. Reaction Information Word Equation … H2 + I2 = HI is a Synthesis reaction where one mole of Dihydrogen [H 2] and one mole of Diiodine [I 2] combine to form two moles of Hydrogen Iodide [HI] Show Chemical … Finally, the standard molar Gibbs Free Energies at 298. What is the mass of HI in the flask? Senior News Reporter.016. What is the rate constant at 645 K? The activation energy for the decomposition of HI(g) to H_2(g) and I_2(g) is 186 kj/mol. Chemistry questions and answers. At equilibrium, the flask contains 90.00 L reaction vessel at 400ºC.10M and [I2]=2. CH 4 (g) + CO 2 (g) ⇌ 2CO(g) + 2H 2 (g); K p = 450.290 at 400 K. 0. Ở nhiệt độ không đổi, khi tăng nồng độ H2 hoặc I2 thì You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Consider the reaction H2(g) + I2(g) <--> 2HI(g). About us. This problem has been solved! \[\ce{H2(g) + I2(g) \rightleftharpoons 2HI(g)} + \text{heat} \label{15.4 x 10^-9 l/(mol x s) at In an experiment, 0. View the full answer.815 atm 2. Question: Consider the equilibrium system involving the decomposition of hydrogen iodide.0049.The amount of I2 produced over time is measured by opening each 2HI(g)⇌H2(g)+I2(g)2HI(g)⇌H2(g)+I2(g) At equilibrium it is found that [HI]=[HI]= 3.336 M hydrogen iodide. The potential energy of the reactants is indicated on the diagram.00 L reaction vessel, chemical analysis determined these concentrations at equilibrium: [H.040. Consider the second-order reaction: 2HI(g)→H2(g)+I2(g) Use the simulation to find the initial concentration [HI]0 and the rate constant k for the reaction. Balance the The oxidation state of an element in its elementary state, such as H₂ or I₂, is always 0. Balance the This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts.25 Consider the reaction: H2 (g) +I2 (g) 2 HI (g) A reaction mixture in a 3. Calculate the concentration of H2 at equilibrium. Chemistry questions and answers.51 x 10^-9 L/mols at 500 K and 1. B) The equilibrium will shift to th; The following reaction is exothermic.16 M and their equilibrium concentrations are both 0.8. Transcribed image text: 25. Hydrogen iodide decomposes according to the equation shown below.00-L reaction The equilibrium constant for the gas phase reaction H2 (g) + I2 (g) 2HI (g) is Keq = 50 at 25 °C. Question: The standard free energy of formation of gaseous hydrogen iodide is1. The equilibrium constant, Kc, for the following reaction is 1. Equilibrium concentration of H1 decreases 3.0500 M . 0. In another study of the formation of HI(g), H2(g) and I2(g) were placed in a sealed container at a certain temperature.15) K p = K ( R T) Δ n. If an additional 1. Part A Calculate the equilibrium constant (Kc) for the reaction at this temperature. Chemistry Chemical Equilibrium Equilibrium Constants.414 M, L) = 0. Solution. What will be the concentration of HI after t = 4. What is the equilibrium constant for the reaction H2 (g)+I2 (g)⇌2HI (g) at 700 K? This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer Balanced Chemical Equation 2 HI → H 2 + I 2 ⬇ Scroll down to see reaction info and a step-by-step answer, or balance another equation.75M and [I2]=2. roughly equal amounts of products and reactants are present d. The equilibrium constant, K c, for the reaction H 2 ( g) + I 2 ( g) ⇄ 2HI ( g) at 425°C is 54. The answer is . Equilibrium concentration of H1 increases 2.09 M .70 M I₂, the what is the equilibrium concentration of HI? MULTIPLE CHOICE. Chemistry questions and answers. You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Hydrogen iodide decomposes according to the equation 2HI(g) H2(g) + I2(g), for which Kc = 0. Bin options: 1. The reaction described by H2 (g) + I2 (g) yields 2HI (g) has an experimentally determined rate law of rate of reaction= k [H2] [I2]some proposed mechanisms for this reaction are: Mechanism a.53×1010 s ([HI]t) for a reaction starting under the condition in the simulation? Given from simulation: Rate Law: k[HI]^2 Question. Consider the following reaction: H2 (g) + I2 (g) ⇌ 2 HI (g) Complete the following table.016 Initially a container contains 0.036. Run in the forward direction to restablish equilibrium. ÐÏ à¡± á> þÿ h j Exercise 14. The potential energy of the reactants is indicated on the diagram.300 mol of I2 were placed in a 1. [4] The reaction will stop. 1)For the reaction in the previous problem, that is, 2HI (g) ↔ H2 (g) + I2 (g) Keq = 0.00160 M-1 . The equilibrium concentration of I2 is 0. Kp = K(RT)Δn (15.Ea = - (8. Assume that all concentrations are equilibrium concentrations in M .6 g HI.550 mol HI was injected into a 2.0 at 700 K what can be said about this reaction at this temperature? A reaction vessel is charged with hydrogen iodide, which partially decomposes to molecular hydrogen and iodine: (2pt) 2HI(g) H2( g)+I2( g) When the system comes to equilibrium at 425∘C,PHi=0.200 M, and [HI] = 3.3 HI(g) 25.0200 M .45 M HI and no product. a.15) (15. Copy link.0156 at 400ºC. The reaction described by H2 (g) + I2 (g) yields 2HI (g) has an experimentally determined rate law of rate of reaction= k [H2] [I2]some proposed mechanisms for this reaction are: Mechanism a.7. Part A.50 s is found to be 0.0 minutes? 1 pts.0244 Question: In an experiment hydrogen iodide was found to be 24.250 M 0 We know the reaction proceeds from left to right because there is no HI present initially and the equilibrium amount of HI is 0.484 M , and [HI]=4.138 M d. What is the reaction quotient, Q, for this system when [H2] = 0. `If 1`.761 g H2 and 96. The reaction rate is a direct function of the reactants concentrations, aA+ bB → cC #"Rate" = k[A]^x [B]^y# Where #a, b, c#: are the stoichiometric coefficients #x, y#: are the reactant orders The … Question: Determine the reaction quotient expression for the reversible reaction below. reactants predominate c. Study with Quizlet and memorize flashcards containing terms like Calculate Kc for the reaction 2HI(g) ⇌ H2(g) + I2(g) given that the concentrations of each species at equilibrium are as follows:[HI] = 0. 0. What is the new partial pressure of HI? H2(g) + I2(g) → 2HI(g) (a) Using the equation ΔH o rxn = ∑(BE(reactants)) − ∑(BE(products)) kJ/mol (b) Using the equation ΔH o rxn = ∑(nΔH o f (products)) − ∑(mΔH o f (reactants)) kJ/mol Bond BE kJ/mol Substance ΔH o f kJ/mol H―H 436. See Answer Question: For the reaction: 2HI (g) ↔ H2 (g) + I2 (g) Keq = 0. Chemistry questions and answers. At this temperature, what is the value of Keq for the equilibrium below? HI (g) ⇌ 1/2 H2 (g) + 1/2 I2 (g) The value of Keq for the equilibrium H2 (g) + I2 (g) 2HI (g) is 794 at 25 °C. Copy link. About Quizlet; How Quizlet works; Careers; Advertise with us; Get the app; For students. Will the equilibrium concentration of HI increase, decrease, or remain See Answer. What is the value of Keq for the equilibrium below? 1/2H₂ (g) + 1/2 I₂ (g) ⇌ HI (g), The value of Keq for the equilibrium H₂ (g) + I₂ (g) ⇌ 2 HI (g) is 794 at 25°C.68×1010 s ([HI]t for a reaction starting under the condition in the simulation? k = 6. at 825 K.80×10-2 at 698 K. If the initial concentration of HI is 4.323 moles of HI are introduced into a 1. HI decomposes to H2 and I2 by the following equation: 2HI (g) → H2 (g) + I2 (g);Kc = 1. In a certain experiment the decomposition of hydrogen iodide on finely divided gold is zeroth order with respect to HI. What is the concentration of HI at equilibrium? Group of answer choices a.393 M.g O2H+g OC⇌g 2H+g 2OC .10 x 10^-5 L/mols at 600 K.50×10-3M at 400 K, which one of the following statements is H2(g) + I2(g) ⇌ 2HI(g) and more. What will be the concentration of HI after t = 1. Khi tăng nhiệt độ, cân bằng trên chuyển dịch theo chiều nghịch.200 M, and [HI] = 3.015 2HI (g) [image] H2 (g) + I2 (g) 6 kJ 9 kJ 15 kJ 20 kJ 22 kJ.59×10 −3 MM , [H2]=[H2]= 4.51x10^-9 L/mols) ( (1/ The value of Keq for the equilibrium H2 (g) + I2 (g) ⇌ 2HI (g) is 794 at 25 °C.94×10-2 at 728 K.0411 0. The decomposition of hydrogen iodide follows the equation 2HI ( g) → H2 ( g) + I2 ( g).215 M H2, and 0.0275 M c.9 = t retfa IH fo noitartnecnoc eht eb lliw tahW .15M, 0.5 k J/m o l r x n H 2 (g) and I 2 (g) can react to produce HI (g) , as represented above. Choose the one alternative that best completes the statement or answers the question. At this temperature, what is the value. What is the reaction quotient, Q, for this system when [H2] = 0. A reaction vessel contains 0.G.4x10^-9 L/mol.65 x 10-2 mol-1 L s-1.95×10-2 at 731 K., When the substances in the equation below are at equilibrium, at pressure P and temperature T, the equilibrium can be shifted to favor the The correct answer is 0. At this temperature, what is the value of Keq for … The equilibrium concentration of I2 is 0.Ea = - (8. The equilibrium reaction can be written as follows: 2HI(g) ⇌ H2(g) + I2(g). H2(g) + I2(g) 2HI(g) Initial 0. Explain the concept of a dynamic equilibrium.85 mol/L, [I2] = 0. Express your answer using two significant figures.8.00 mol of HI(g) is introduced into the reaction vessel, what are 2HI(g)⇌H2(g)+I2(g) Select the correct answer below: Qc=[HI]2[H2][I2] Qc=[H2][I2][HI] Qc=[H2][I2][HI]2.5, What were the equilibrium concentration for H2, I2 and HI? N2 (g) + 3 H2 (g) ↔ 2 NH3 (g) ΔH = −92kJ/mol. Hydrogen iodide decomposes according to the equation 2HI (g) H2(g) + I2(g), Question: Consider the second-order reaction: 2HI(g)→H2(g)+I2(g) Use the simulation to find the initial concentration [HI]0 and the rate constant k for the reaction.27 mol/L.0900 MM . Which statement is correct about this reaction mixture? Expert Answer.30 kJ/mol at 25°C.60 M HI, 0.